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Oracle Database SQL Sample Questions (Q61-Q66):

NEW QUESTION # 61
You have the privileges to create any type of synonym.
Which stalement will create a synonym called EMP for the HCM.EMPLOYEE_RECORDS table that is accesible to all users?

A. CREATE SYNONYM PUBLIC.emp FOR hcm.employee_records;
B. CREATE SYNONYM SYS.emp FOR hcm.employee_records;
C. CREATE GLOBAL SYNONYM emp FOR hcm.employee_records;
D. CREATE PUBLIC SYNONYM emp FOR hcm. employee_records;
E. CREATE SYNONYM emp FOR hcm.employee_records;

Answer: D

Explanation:
Synonyms in Oracle are aliases for database objects that can simplify SQL statements for database users.
A: The term "GLOBAL" is not used in the creation of synonyms in Oracle.
B: The statement without the keyword PUBLIC will create a private synonym that is only accessible to the user creating the synonym, not all users.
C: The correct syntax does not include PUBLIC as a prefix to the synonym name itself, making this option incorrect.
D: You cannot specify the SYS schema for creating synonyms, as it is reserved for system objects.
E: This is the correct syntax to create a public synonym, which makes the underlying object accessible to all users.
References:
* Oracle Database SQL Language Reference, 12c Release 1 (12.1): "CREATE SYNONYM"

NEW QUESTION # 62
Which two statements are true about Oracle synonyms? (Choose two.)

A. All private synonym names must be unique in the database.
B. A synonym has an object number.
C. A synonym can be created on an object in a package.
D. A synonym can have a synonym.
E. Any user can create a PUBLICsynonym.

Answer: A,C

Explanation:
Explanation/Reference: https://docs.oracle.com/cd/B19306_01/server.102/b14200/statements_7001.htm

NEW QUESTION # 63
Examine the structure of the EMPLOYEES table.
You must display the details of employees who have manager with MANAGER_ID 100, who were hired in the past 6 months and who have salaries greater than 10000.
Which query would retrieve the required result?

A. SELECT last_name, hire_date, salaryFROM employeesWHERE manager_id = (SELECT employee_id FROM employees WHERE employee_id = 100)UNION ALL(SELECT last_name, hire_date, salaryFROM employeesWHERE hire_date > SYSDATE-180INTERSECTSELECT last_name, hire_date, salaryFROM employeesWHERE salary > 10000);
B. SELECT last_name, hire_date, salaryFROM employeesWHERE salary > 10000UNION ALLSELECT last_name, hire_date, salaryFROM employeesWHERE manager_ID = (SELECT employee_id FROM employees WHERE employee_id = 100)INTERSECTSELECT last_name, hire_date, salaryFROM employeesWHERE hire_date > SYSDATE-180;
C. SELECT last_name, hire_date, salaryFROM employeesWHERE manager_id = (SELECT employee_id FROM employees WHERE employee_id = '100')UNIONSELECT last_name, hire_date, salaryFROM employeesWHERE hire_date > SYSDATE-180INTERSECTSELECT last_name, hire_date, salaryFROM employeesWHERE salary > 10000;
D. (SELECT last_name, hire_date, salaryFROM employeesWHERE salary > 10000UNION ALLSELECT last_name, hire_date, salaryFROM employeesWHERE manager_ID = (SELECT employee_id FROM employees WHERE employee_id = 100))UNIONSELECT last_name, hire_date, salaryFROM employeesWHERE hire_date > SYSDATE-180;

Answer: C

NEW QUESTION # 64
View the Exhibit and examine the structure of the EMPLOYEES table.
You want to display all employees and their managers having 100 as the MANAGER_ID.
You want the output in two columns: the first column would have the LAST_NAME of the managers and the second column would have LAST_NAME of the employees.
Which SQL statement would you execute?

A. SELECT m.last_name "Manager", e.last_name "Employee"
FROM employees m JOIN employees e
ON m.employee_id = e.manager_id
WHERE e.managerjd=100;
B. SELECT m.last_name "Manager", e.last_name "Employee"
FROM employees m JOIN employees e
ON e.employee_id = m.manager_id
WHERE m.manager_id=100;
C. SELECT m.last_name "Manager", e.last_name "Employee"
FROM employees m JOIN employees e
WHERE m.employee_id = e.manager_id AND e.managerjd=100;
D. SELECT m.last_name "Manager", e.last_name "Employee"
FROM employees m JOIN employees e
ON m.employee_id = e.manager_id
WHERE m.manager_id=100;

Answer: A

NEW QUESTION # 65
Which statement is true about transactions?

A. A set of DDL statements executed in a sequence ending with a COMMIT forms a single transaction.
B. A set of Data Manipulation Language (DML) statements executed in a sequence ending with a SAVEPOINT forms a single transaction.
C. A combination of DDL and DML statements executed in a sequence ending with a COMMIT forms a single transaction.
D. Each Data Definition Language (DDL) statement executed forms a single transaction.

Answer: D

Explanation:
References:
https://docs.oracle.com/database/121/CNCPT/transact.htm#CNCPT038

NEW QUESTION # 66
......

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